Skip to main content

2220. Minimum Bit Flips to Convert Number

Published 1 min readMarkdown
Part of seriesLeetCode Daily Question

A bit flip of a number x is choosing a bit in the binary representation of x and flipping it from either 0 to 1 or 1 to 0.

  • For example, for x = 7, the binary representation is 111 and we may choose any bit (including any leading zeros not shown) and flip it. We can flip the first bit from the right to get 110, flip the second bit from the right to get 101, flip the fifth bit from the right (a leading zero) to get 10111, etc.

Given two integers start and goal, return the minimum number of bit flips to convert start to goal.

Thoughts

  • I accidentally solved this one before I even had a chance to write down my thoughts about it 💀

Solution

class Solution {
    public int minBitFlips(int start, int goal) {
        return Integer.bitCount(start ^ goal);
    }
}

Time Complexity: O(1)
Space Complexity: O(1)

Conclusion

Idek what to say about this one it was so simple 💀

No comments yet. Be the first to comment.